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0=6x^2-18x-24
We move all terms to the left:
0-(6x^2-18x-24)=0
We add all the numbers together, and all the variables
-(6x^2-18x-24)=0
We get rid of parentheses
-6x^2+18x+24=0
a = -6; b = 18; c = +24;
Δ = b2-4ac
Δ = 182-4·(-6)·24
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-30}{2*-6}=\frac{-48}{-12} =+4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+30}{2*-6}=\frac{12}{-12} =-1 $
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